Solution: Linked List Cycle III
Let’s solve the Linked List Cycle III problem using the Fast and Slow Pointers pattern.
We'll cover the following...
We'll cover the following...
Statement
Given the head
of a linked list, determine the length of the cycle present in the linked list. If there is no cycle, return 0
.
A cycle exists in a linked list if there is some node in the list that can be reached again by continuously following the next
pointer.
Constraints:
The number of nodes in the list is in the range
. ...